What is the sum from n=2 to infinity of 1/((2n+7)^3) ?

The sum from n=2 to infinity of 1/((2n+7)^3) is converges

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sum from n=2 to infinity of 1/((2n+7)^3)

n = 2 \sum \infty \frac{1}{( 2 n + 7 ) ^{3}}

converges

Solution steps

n = 2 \sum \infty \frac{1}{( 2 n + 7 ) ^{3}}

Apply Series Comparison Test:

converges

= converges

e^{3 x^{3}}

\int_{1}^{2} (x^{5} + x^{- 5}) d x

\int x^{3} (2 + x^{4})^{5} d x

\frac{\partial}{\partial y} (- x sin (x y))

f (x) = \frac{8}{x ^{3}}

What is the sum from n=2 to infinity of 1/((2n+7)^3) ?
The sum from n=2 to infinity of 1/((2n+7)^3) is converges