What is the integral of (e^{-x^2})/(x^2) ?

The integral of (e^{-x^2})/(x^2) is -(e^{-x^2})/x-sqrt(pi)\erf(x)+C

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integral of (e^{-x^2})/(x^2)

\int \frac{e ^{- x^{2}}}{x ^{2}} d x

- \frac{e ^{- x^{2}}}{x} - π erf (x) + C

Solution steps

\int \frac{e ^{- x^{2}}}{x ^{2}} d x

Apply Integration By Parts

: - \frac{e ^{- x^{2}}}{x} - \int 2 e^{- x^{2}} d x

= - \frac{e ^{- x^{2}}}{x} - \int 2 e^{- x^{2}} d x

\int 2 e^{- x^{2}} d x = π erf (x)

= - \frac{e ^{- x^{2}}}{x} - π erf (x)

Add a constant to the solution

= - \frac{e ^{- x^{2}}}{x} - π erf (x) + C

(20.8) (9.16)

\int 20 x^{3} + 12 x^{2} + 6 d x

\int cos^{3} (x) ln (sin (x)) d x

f (x) = \frac{3 x + 2}{3 x - 2}

\frac{d}{d x} (3 x + 2 y)

What is the integral of (e^{-x^2})/(x^2) ?
The integral of (e^{-x^2})/(x^2) is -(e^{-x^2})/x-sqrt(pi)\erf(x)+C