What is the integral of 11sec^2(x) ?

The integral of 11sec^2(x) is 11tan(x)+C

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integral of 11sec^2(x)

\int 11 sec^{2} (x) d x

11 tan (x) + C

Solution steps

\int 11 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 11 \cdot \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 11 tan (x)

Add a constant to the solution

= 11 tan (x) + C

\int_{0}^{π} 9 sin^{2} (2 x) d x

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\frac{\partial}{\partial x} (5 x^{5} y^{4} + 7 x^{6} y^{8})

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n = 2 \sum \infty (\frac{2}{π})^{n}