What is (\partial)/(\partial y)(sin(2x+3y)) ?

The answer to (\partial)/(\partial y)(sin(2x+3y)) is cos(2x+3y)*3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(sin(2x+3y))

\frac{\partial}{\partial y} (sin (2 x + 3 y))

cos (2 x + 3 y) \cdot 3

Solution steps

\frac{\partial}{\partial y} (sin (2 x + 3 y))

Treat

x

as a constant

Apply the chain rule:

cos (2 x + 3 y) \frac{\partial}{\partial y} (2 x + 3 y)

= cos (2 x + 3 y) \frac{\partial}{\partial y} (2 x + 3 y)

\frac{\partial}{\partial y} (2 x + 3 y) = 3

= cos (2 x + 3 y) \cdot 3

n = 0 \sum \infty (\frac{π}{3})^{n}

x \to 0 lim (\frac{tan ( x )}{x})

(- 1, 4), (- 3, - 1)

f (x) = lo g_{2} (4 x)

\frac{\partial}{\partial y} (tan (x y^{2}))

What is (\partial)/(\partial y)(sin(2x+3y)) ?
The answer to (\partial)/(\partial y)(sin(2x+3y)) is cos(2x+3y)*3