What is laplacetransform 10sin(80pit) ?

The answer to laplacetransform 10sin(80pit) is (800pi)/(s^2+6400pi^2)

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laplacetransform 10sin(80pit)

laplace transform

10 sin (80 π t)

\frac{800 π}{s ^{2} + 6400 π ^{2}}

Solution steps

L {10 sin (80 π t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 10 L {sin (80 π t)}

L {sin (80 π t)} : \frac{80 π}{s ^{2} + 6400 π ^{2}}

= 10 \cdot \frac{80 π}{s ^{2} + 6400 π ^{2}}

Refine

10 \frac{80 π}{s ^{2} + 6400 π ^{2}} : \frac{800 π}{s ^{2} + 6400 π ^{2}}

= \frac{800 π}{s ^{2} + 6400 π ^{2}}

\frac{\partial}{\partial x} (\frac{4}{3} π y^{2} x)

x \to 2 lim (x - 1)

\frac{\partial}{\partial x} (4 x^{3} - 4 x)

π x

\int \frac{1}{sin ( a x + b )} d x

What is laplacetransform 10sin(80pit) ?
The answer to laplacetransform 10sin(80pit) is (800pi)/(s^2+6400pi^2)