What is (\partial)/(\partial x)(4x^3-4x) ?

The answer to (\partial)/(\partial x)(4x^3-4x) is 12x^2-4

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(\partial)/(\partial x)(4x^3-4x)

\frac{\partial}{\partial x} (4 x^{3} - 4 x)

12 x^{2} - 4

Solution steps

\frac{\partial}{\partial x} (4 x^{3} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x^{3}) - \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (4 x^{3}) = 12 x^{2}

\frac{\partial}{\partial x} (4 x) = 4

= 12 x^{2} - 4

π x

\int \frac{1}{sin ( a x + b )} d x

\frac{d y}{d x} = 6 x + y - 6

\int \frac{7 x ^{2} + 4 x + 7}{x ^{3} - 1} d x

\int_{- 3}^{3} (\frac{18}{9 + x ^{2}} - 1) d x

What is (\partial)/(\partial x)(4x^3-4x) ?
The answer to (\partial)/(\partial x)(4x^3-4x) is 12x^2-4