What is the integral from-3 to 3 of ((18)/(9+x^2)-1) ?

The integral from-3 to 3 of ((18)/(9+x^2)-1) is 3pi-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-3 to 3 of ((18)/(9+x^2)-1)

\int_{- 3}^{3} (\frac{18}{9 + x ^{2}} - 1) d x

3 π - 6

Decimal Notation

3.42477 \dots

Solution steps

\int_{- 3}^{3} \frac{18}{9 + x ^{2}} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 3}^{3} \frac{18}{9 + x ^{2}} d x - \int_{- 3}^{3} 1 d x

\int_{- 3}^{3} \frac{18}{9 + x ^{2}} d x = 3 π

\int_{- 3}^{3} 1 d x = 6

= 3 π - 6

x \to - \infty lim (∣ x ∣)

2 \frac{d y}{d x} + 4 y = - 8 y^{3}

\frac{\partial}{\partial x} (3 (y + 4) (x - 5)^{3})

\frac{d}{d x} (x^{2} 2 x - 5)

\int \frac{1}{2 π} e^{\frac{- x ^{2}}{2}} d x

What is the integral from-3 to 3 of ((18)/(9+x^2)-1) ?
The integral from-3 to 3 of ((18)/(9+x^2)-1) is 3pi-6