What is the solution for 2(dy)/(dx)+4y=-8y^3 ?

The solution for 2(dy)/(dx)+4y=-8y^3 is y=sqrt(1/(e^{4x-c_{1))-2}},y=-sqrt(1/(e^{4x-c_{1))-2}}

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2(dy)/(dx)+4y=-8y^3

2 \frac{d y}{d x} + 4 y = - 8 y^{3}

y = \frac{1}{e ^{4 x - c_{1}} - 2}, y = - \frac{1}{e ^{4 x - c_{1}} - 2}

Solution steps

2 \frac{d y}{d x} + 4 y = - 8 y^{3}

Solve Bernoulli ODE:

y = \frac{1}{e ^{4 x - c_{1}} - 2}, y = - \frac{1}{e ^{4 x - c_{1}} - 2}

y = \frac{1}{e ^{4 x - c_{1}} - 2}, y = - \frac{1}{e ^{4 x - c_{1}} - 2}

\frac{\partial}{\partial x} (3 (y + 4) (x - 5)^{3})

\frac{d}{d x} (x^{2} 2 x - 5)

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x \to 0 lim (e^{x^{3}})

\int sin (4) (x) d x

What is the solution for 2(dy)/(dx)+4y=-8y^3 ?
The solution for 2(dy)/(dx)+4y=-8y^3 is y=sqrt(1/(e^{4x-c_{1))-2}},y=-sqrt(1/(e^{4x-c_{1))-2}}