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Popular >

y^'=(x+y)^2

Solution

y^{^{'}} = (x + y)^{2}

Solution

y = tan (x + c_{1}) - x

Solution steps

y^{'} (x) = (x + y)^{2}

Solve using substitution:

y = tan (x + c_{1}) - x

y = tan (x + c_{1}) - x

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(x+y)^2 ?
The solution for y^'=(x+y)^2 is y=tan(x+c_{1})-x