What is the derivative of (3+4x-x^2^{1/2}) ?

The derivative of (3+4x-x^2^{1/2}) is (-x+2)/((3+4x-x^2)^{1/2)}

What is the first derivative of (3+4x-x^2^{1/2}) ?

The first derivative of (3+4x-x^2^{1/2}) is (-x+2)/((3+4x-x^2)^{1/2)}

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\frac{d}{d x} ((3 + 4 x - x^{2})^{\frac{1}{2}})

\frac{- x + 2}{( 3 + 4 x - x ^{2} ) ^{\frac{1}{2}}}

Solution steps

\frac{d}{d x} ((3 + 4 x - x^{2})^{\frac{1}{2}})

Apply the chain rule:

\frac{1}{2 ( 3 + 4 x - x ^{2} ) ^{\frac{1}{2}}} \frac{d}{d x} (3 + 4 x - x^{2})

= \frac{1}{2 ( 3 + 4 x - x ^{2} ) ^{\frac{1}{2}}} \frac{d}{d x} (3 + 4 x - x^{2})

\frac{d}{d x} (3 + 4 x - x^{2}) = - 2 x + 4

= \frac{1}{2 ( 3 + 4 x - x ^{2} ) ^{\frac{1}{2}}} (- 2 x + 4)

Simplify

\frac{1}{2 ( 3 + 4 x - x ^{2} ) ^{\frac{1}{2}}} (- 2 x + 4) : \frac{- x + 2}{( 3 + 4 x - x ^{2} ) ^{\frac{1}{2}}}

= \frac{- x + 2}{( 3 + 4 x - x ^{2} ) ^{\frac{1}{2}}}

y^{^{''}} + 4 y = 2 t^{2}

f (x) = 4 x^{2} - 2 x + 3

\frac{d}{d x} (lo g_{e} (tan (x)))

\frac{d}{d x} (\frac{x ^{2} - 8 x}{2 x - 3})

\int - \frac{1}{2 x} d x

What is the derivative of (3+4x-x^2^{1/2}) ?
The derivative of (3+4x-x^2^{1/2}) is (-x+2)/((3+4x-x^2)^{1/2)}
What is the first derivative of (3+4x-x^2^{1/2}) ?
The first derivative of (3+4x-x^2^{1/2}) is (-x+2)/((3+4x-x^2)^{1/2)}