What is the derivative of h(w)=(4w^5-w)/w ?

The derivative of h(w)=(4w^5-w)/w is 16w^3

What is the first derivative of h(w)=(4w^5-w)/w ?

The first derivative of h(w)=(4w^5-w)/w is 16w^3

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derivative of

h (w) = \frac{4 w ^{5} - w}{w}

16 w^{3}

Solution steps

\frac{d}{d w} (\frac{4 w ^{5} - w}{w})

Simplify

\frac{4 w ^{5} - w}{w} : 4 w^{4} - 1

= \frac{d}{d w} (4 w^{4} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d w} (4 w^{4}) - \frac{d}{d w} (1)

\frac{d}{d w} (4 w^{4}) = 16 w^{3}

\frac{d}{d w} (1) = 0

= 16 w^{3} - 0

Simplify

= 16 w^{3}

\int x e^{1 - x} d x

f (x) = x sin (\frac{1}{x})

y = x^{2} - 3 x - 2, (2, - 4)

x = 2 - y^{2}, x = y^{4}

x \to 3 - lim (\frac{4}{x ^{2} - 9})

What is the derivative of h(w)=(4w^5-w)/w ?
The derivative of h(w)=(4w^5-w)/w is 16w^3
What is the first derivative of h(w)=(4w^5-w)/w ?
The first derivative of h(w)=(4w^5-w)/w is 16w^3