What is the derivative of 8xe^{-x} ?

The derivative of 8xe^{-x} is 8(e^{-x}-e^{-x}x)

What is the first derivative of 8xe^{-x} ?

The first derivative of 8xe^{-x} is 8(e^{-x}-e^{-x}x)

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\frac{d}{d x} (8 x e^{- x})

8 (e^{- x} - e^{- x} x)

Solution steps

\frac{d}{d x} (8 x e^{- x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x e^{- x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{- x}

= 8 (\frac{d x}{d x} e^{- x} + \frac{d}{d x} (e^{- x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{- x}) = - e^{- x}

= 8 (1 \cdot e^{- x} + (- e^{- x}) x)

Simplify

= 8 (e^{- x} - e^{- x} x)

x \to 0 lim (1 - e^{x})

\frac{d}{d x} (a sin (3 x))

\frac{d}{d x} (2 y sin (x))

\int \frac{1}{e ^{2}} d x

x \to - 1 - lim (\frac{x}{x ^{2} - 1})

What is the derivative of 8xe^{-x} ?
The derivative of 8xe^{-x} is 8(e^{-x}-e^{-x}x)
What is the first derivative of 8xe^{-x} ?
The first derivative of 8xe^{-x} is 8(e^{-x}-e^{-x}x)