What is the derivative of 2ysin(x) ?

The derivative of 2ysin(x) is 2((dy)/(dx)sin(x)+cos(x)y)

What is the first derivative of 2ysin(x) ?

The first derivative of 2ysin(x) is 2((dy)/(dx)sin(x)+cos(x)y)

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\frac{d}{d x} (2 y sin (x))

2 (\frac{d y}{d x} sin (x) + cos (x) y)

Solution steps

\frac{d}{d x} (2 y sin (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (y sin (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = y, g = sin (x)

= 2 (\frac{d y}{d x} sin (x) + \frac{d}{d x} (sin (x)) y)

\frac{d}{d x} (sin (x)) = cos (x)

= 2 (\frac{d y}{d x} sin (x) + cos (x) y)

\int \frac{1}{e ^{2}} d x

x \to - 1 - lim (\frac{x}{x ^{2} - 1})

x \to \infty lim (2 e^{x})

(6, 6), (- 10, - 7)

\frac{d}{d t} (e^{t} + e^{- t} + t)

What is the derivative of 2ysin(x) ?
The derivative of 2ysin(x) is 2((dy)/(dx)sin(x)+cos(x)y)
What is the first derivative of 2ysin(x) ?
The first derivative of 2ysin(x) is 2((dy)/(dx)sin(x)+cos(x)y)