What is the solution for (dy}{dx}-y/x =y^2\frac{sin(x))/x ?

The solution for (dy}{dx}-y/x =y^2\frac{sin(x))/x is y= x/(cos(x)+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}-y/x =y^2\frac{sin(x))/x

\frac{d y}{d x} - \frac{y}{x} = y^{2} \frac{sin ( x )}{x}

y = \frac{x}{cos ( x ) + c _{1}}

Solution steps

\frac{d y}{d x} - \frac{y}{x} = y^{2} \frac{sin ( x )}{x}

Solve Bernoulli ODE:

y = \frac{x}{cos ( x ) + c _{1}}

y = \frac{x}{cos ( x ) + c _{1}}

\int_{0}^{4} 4 e^{- 3 x} d x

\frac{d}{d x} (e^{- x} cos (x) - e^{- x} sin (x))

\frac{d y}{d x} + 3 y = x^{2}

\int \frac{tan ^{3} ( θ )}{cos ^{2} ( θ )} d θ

f (x) = x^{2} - 3 x + 2, at x = 1

What is the solution for (dy}{dx}-y/x =y^2\frac{sin(x))/x ?
The solution for (dy}{dx}-y/x =y^2\frac{sin(x))/x is y= x/(cos(x)+c_{1)}