What is the integral from 1 to 5 of 2/(x^3) ?

The integral from 1 to 5 of 2/(x^3) is 24/25

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integral from 1 to 5 of 2/(x^3)

\int_{1}^{5} \frac{2}{x ^{3}} d x

\frac{24}{25}

Decimal Notation

0.96

Solution steps

\int_{1}^{5} \frac{2}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{5} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{5}

= 2 [- \frac{1}{2 x ^{2}}]_{1}^{5}

Compute the boundaries:

\frac{12}{25}

= 2 \cdot \frac{12}{25}

Simplify

= \frac{24}{25}

\frac{d}{d x} (arctan (x - 1))

\frac{d}{d x} (\frac{5}{e ^{x} + x})

x \to 1 + lim ((x - 3)^{2})

y^{^{''}} - 4 y^{^{'}} + 29 y = 0

\frac{d}{d x} (\frac{2 e ^{x} - x ^{5}}{1 - 3 x ^{5}})

What is the integral from 1 to 5 of 2/(x^3) ?
The integral from 1 to 5 of 2/(x^3) is 24/25