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Popular >

y^'=2xy,y(0)=1

Solution

y^{^{'}} = 2 x y, y (0) = 1

Solution

y = e^{x^{2}}

Solution steps

y^{'} (x) = 2 x y

Solve separable ODE:

y = e^{x^{2}}

y = e^{x^{2}}

Popular Examples

(xy)dx+(x^2+y^2)dy=0

(x y) d x + (x^{2} + y^{2}) d y = 0

integral of x/(\sqrt[4]{x^2+2)}

expand 2(x-6)^3 expand

2 (x - 6)^{3}

limit as z approaches 0 of z^3cos(1/z)

z \to 0 lim (z^{3} cos (\frac{1}{z}))

tangent of f(x)=3sec(x),\at x= pi/3 tangent of

f (x) = 3 sec (x), at x = \frac{π}{3}

Frequently Asked Questions (FAQ)

What is the solution for y^'=2xy,y(0)=1 ?
The solution for y^'=2xy,y(0)=1 is y=e^{x^2}