What is the tangent of f(x)=3sec(x),\at x= pi/3 ?

The tangent of f(x)=3sec(x),\at x= pi/3 is y=6sqrt(3)x+6-2sqrt(3)pi

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tangent of f(x)=3sec(x),\at x= pi/3

tangent of

f (x) = 3 sec (x), at x = \frac{π}{3}

y = 63 x + 6 - 23 π

Solution steps

Find the tangent point:

(\frac{π}{3}, 6)

Find the slope of

f (x) = 3 sec (x) : \frac{df ( x )}{d x} = 3 sec (x) tan (x)

Compute the slope of

f (x) = 3 sec (x)

x = \frac{π}{3} : m = 63

Find the line with slope m=

63

and passing through

(\frac{π}{3}, 6) : y = 63 x + 6 - 23 π

y = 63 x + 6 - 23 π

cos^{3} (e^{4 x})

y = x^{2} - x + 7

\frac{d x}{d t} = 3 x t^{2} - 3 t^{2}

\int_{0}^{l n (5)} e^{x} - e^{- 3 x} d x

What is the tangent of f(x)=3sec(x),\at x= pi/3 ?
The tangent of f(x)=3sec(x),\at x= pi/3 is y=6sqrt(3)x+6-2sqrt(3)pi