What is the derivative of y=-8e^{-2x}-9e^{2x}-5e^x ?

The derivative of y=-8e^{-2x}-9e^{2x}-5e^x is 16e^{-2x}-18e^{2x}-5e^x

What is the first derivative of y=-8e^{-2x}-9e^{2x}-5e^x ?

The first derivative of y=-8e^{-2x}-9e^{2x}-5e^x is 16e^{-2x}-18e^{2x}-5e^x

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derivative of

y = - 8 e^{- 2 x} - 9 e^{2 x} - 5 e^{x}

16 e^{- 2 x} - 18 e^{2 x} - 5 e^{x}

Solution steps

\frac{d}{d x} (- 8 e^{- 2 x} - 9 e^{2 x} - 5 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (8 e^{- 2 x}) - \frac{d}{d x} (9 e^{2 x}) - \frac{d}{d x} (5 e^{x})

\frac{d}{d x} (8 e^{- 2 x}) = - 16 e^{- 2 x}

\frac{d}{d x} (9 e^{2 x}) = 18 e^{2 x}

\frac{d}{d x} (5 e^{x}) = 5 e^{x}

= - (- 16 e^{- 2 x}) - 18 e^{2 x} - 5 e^{x}

Simplify

= 16 e^{- 2 x} - 18 e^{2 x} - 5 e^{x}

9 sin (3 x)

\int 1 - 49 x^{2} d x

\int_{0}^{9} 2 x - \frac{2 x}{3} d x

S (t) = \frac{60 t ^{2}}{t ^{2} + 150}

x x^{2} + 60 (2.9)

What is the derivative of y=-8e^{-2x}-9e^{2x}-5e^x ?
The derivative of y=-8e^{-2x}-9e^{2x}-5e^x is 16e^{-2x}-18e^{2x}-5e^x
What is the first derivative of y=-8e^{-2x}-9e^{2x}-5e^x ?
The first derivative of y=-8e^{-2x}-9e^{2x}-5e^x is 16e^{-2x}-18e^{2x}-5e^x