What is the derivative of f(x)=x^2-3x+4 ?

The derivative of f(x)=x^2-3x+4 is 2x-3

What is the first derivative of f(x)=x^2-3x+4 ?

The first derivative of f(x)=x^2-3x+4 is 2x-3

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derivative of

f (x) = x^{2} - 3 x + 4

2 x - 3

Solution steps

\frac{d}{d x} (x^{2} - 3 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= 2 x - 3 + 0

Simplify

= 2 x - 3

x \to - 8 lim (4 x - 2)

\frac{\partial}{\partial y} (\frac{x}{( y + z )})

\frac{\partial}{\partial x} (x ln (x))

\frac{d}{d x} (2 x + \frac{200}{x})

f (x) = \frac{32}{0}

What is the derivative of f(x)=x^2-3x+4 ?
The derivative of f(x)=x^2-3x+4 is 2x-3
What is the first derivative of f(x)=x^2-3x+4 ?
The first derivative of f(x)=x^2-3x+4 is 2x-3