What is taylor f(x)=e^{-2x} ?

The answer to taylor f(x)=e^{-2x} is 1-2x+2x^2-4/3 x^3+2/3 x^4+\ldots

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taylor f(x)=e^{-2x}

taylor

f (x) = e^{- 2 x}

1 - 2 x + 2 x^{2} - \frac{4}{3} x^{3} + \frac{2}{3} x^{4} + \dots

Solution steps

Apply the Taylor Formula

= 1 + \frac{\frac{d}{d x} ( e ^{- 2 x} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( e ^{- 2 x} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( e ^{- 2 x} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{- 2}{1 !} x + \frac{4}{2 !} x^{2} + \frac{- 8}{3 !} x^{3} + \frac{16}{4 !} x^{4} + \dots

Refine

= 1 - 2 x + 2 x^{2} - \frac{4}{3} x^{3} + \frac{2}{3} x^{4} + \dots

e^{x + 9}

\frac{1}{x ^{2}} \frac{d y}{d x} = 25 + 14 y

f (x) = 8 sin (2 x^{4})

f (x) = x x, at x = 16

\int sec^{2} (4 x t a) n^{5} 4 x d x

What is taylor f(x)=e^{-2x} ?
The answer to taylor f(x)=e^{-2x} is 1-2x+2x^2-4/3 x^3+2/3 x^4+\ldots