What is the derivative of f(x)=8sin(2x^4) ?

The derivative of f(x)=8sin(2x^4) is 64x^3cos(2x^4)

What is the first derivative of f(x)=8sin(2x^4) ?

The first derivative of f(x)=8sin(2x^4) is 64x^3cos(2x^4)

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derivative of

f (x) = 8 sin (2 x^{4})

64 x^{3} cos (2 x^{4})

Solution steps

\frac{d}{d x} (8 sin (2 x^{4}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (sin (2 x^{4}))

Apply the chain rule:

cos (2 x^{4}) \frac{d}{d x} (2 x^{4})

= cos (2 x^{4}) \frac{d}{d x} (2 x^{4})

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

= 8 cos (2 x^{4}) \cdot 8 x^{3}

Simplify

= 64 x^{3} cos (2 x^{4})

f (x) = x x, at x = 16

\int sec^{2} (4 x t a) n^{5} 4 x d x

\int \frac{x ^{3} + 2 x ^{2}}{x} d x

\frac{d}{d x} ((1 + 3 x)^{2})

6 y^{^{''}} - 5 y^{^{'}} + y = 0

What is the derivative of f(x)=8sin(2x^4) ?
The derivative of f(x)=8sin(2x^4) is 64x^3cos(2x^4)
What is the first derivative of f(x)=8sin(2x^4) ?
The first derivative of f(x)=8sin(2x^4) is 64x^3cos(2x^4)