What is the derivative of (1+3x^2) ?

The derivative of (1+3x^2) is 6(1+3x)

What is the first derivative of (1+3x^2) ?

The first derivative of (1+3x^2) is 6(1+3x)

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\frac{d}{d x} ((1 + 3 x)^{2})

6 (1 + 3 x)

Solution steps

\frac{d}{d x} ((1 + 3 x)^{2})

Apply the chain rule:

2 (1 + 3 x) \frac{d}{d x} (1 + 3 x)

= 2 (1 + 3 x) \frac{d}{d x} (1 + 3 x)

\frac{d}{d x} (1 + 3 x) = 3

= 2 (1 + 3 x) \cdot 3

Simplify

= 6 (1 + 3 x)

6 y^{^{''}} - 5 y^{^{'}} + y = 0

x \to 0 lim (e^{s i n (x)})

sec^{2} (x), 8 cos (x)

x \to 3 lim (c x^{2} - 4 x)

\frac{d}{d x} (\frac{( 1 - 4 e ^{x} )}{1 - 5 cos ( x )})

What is the derivative of (1+3x^2) ?
The derivative of (1+3x^2) is 6(1+3x)
What is the first derivative of (1+3x^2) ?
The first derivative of (1+3x^2) is 6(1+3x)