What is the tangent of y=2e^x+x,(0,2) ?

The tangent of y=2e^x+x,(0,2) is y=3x+2

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tangent of y=2e^x+x,(0,2)

tangent of

y = 2 e^{x} + x, (0, 2)

y = 3 x + 2

Solution steps

Find the slope of

y = 2 e^{x} + x : \frac{d y}{d x} = 2 e^{x} + 1

Compute the slope of

y = 2 e^{x} + x

(0, 2) : m = 3

Find the line with slope m=

3

and passing through

(0, 2) : y = 3 x + 2

y = 3 x + 2

y = 6 x + 3

\int \frac{1}{16} d x

f (x) = \frac{48}{x ^{4}}

m = 1 \sum \infty 5^{m - 1}

k = 0 \sum \infty (5 x)^{k}