What is the derivative of f(x)=(48)/(x^4) ?

The derivative of f(x)=(48)/(x^4) is -(192)/(x^5)

What is the first derivative of f(x)=(48)/(x^4) ?

The first derivative of f(x)=(48)/(x^4) is -(192)/(x^5)

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derivative of

f (x) = \frac{48}{x ^{4}}

- \frac{192}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{48}{x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 48 \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 48 \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 48 (- 4 x^{- 4 - 1})

Simplify

48 (- 4 x^{- 4 - 1}) : - \frac{192}{x ^{5}}

= - \frac{192}{x ^{5}}

m = 1 \sum \infty 5^{m - 1}

k = 0 \sum \infty (5 x)^{k}

x \to \infty lim (4^{- x})

\frac{\partial}{\partial x} (\frac{1}{2 x})

\frac{d}{d t} (k t e^{3 t})

What is the derivative of f(x)=(48)/(x^4) ?
The derivative of f(x)=(48)/(x^4) is -(192)/(x^5)
What is the first derivative of f(x)=(48)/(x^4) ?
The first derivative of f(x)=(48)/(x^4) is -(192)/(x^5)