What is the derivative of 1+(2/5)x(2/3)-sqrt(25) ?

The derivative of 1+(2/5)x(2/3)-sqrt(25) is 0+(2/5)(2/3)*1-0

What is the first derivative of 1+(2/5)x(2/3)-sqrt(25) ?

The first derivative of 1+(2/5)x(2/3)-sqrt(25) is 0+(2/5)(2/3)*1-0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

1 + (\frac{2}{5})^{\circ} x (\frac{2}{3})^{\circ} - 25

0 + (\frac{2}{5})^{\circ} (\frac{2}{3})^{\circ} \cdot 1 - 0

Solution steps

\frac{d}{d x} (1 + (\frac{2}{5})^{\circ} x (\frac{2}{3})^{\circ} - 25)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} ((\frac{2}{5})^{\circ} x (\frac{2}{3})^{\circ}) - \frac{d}{d x} (25)

\frac{d}{d x} (1) = 0

\frac{d}{d x} ((\frac{2}{5})^{\circ} x (\frac{2}{3})^{\circ}) = (\frac{2}{5})^{\circ} (\frac{2}{3})^{\circ} \cdot 1

\frac{d}{d x} (25) = 0

= 0 + (\frac{2}{5})^{\circ} (\frac{2}{3})^{\circ} \cdot 1 - 0

g (x) = [ln (5 x - 2)]^{4}

\frac{1}{12 x ^{3}}

\int_{0}^{\infty} \frac{4}{x ^{2} + 4} d x

\frac{d}{d x} (tan (e^{x}))

n = 1 \sum \infty (- 1)^{n} n x^{n}

What is the derivative of 1+(2/5)x(2/3)-sqrt(25) ?
The derivative of 1+(2/5)x(2/3)-sqrt(25) is 0+(2/5)(2/3)*1-0
What is the first derivative of 1+(2/5)x(2/3)-sqrt(25) ?
The first derivative of 1+(2/5)x(2/3)-sqrt(25) is 0+(2/5)(2/3)*1-0