What is the derivative of \sqrt[7]{x^2}+2sqrt(x^5) ?

The derivative of \sqrt[7]{x^2}+2sqrt(x^5) is (2+35x^{31/14})/(7x^{5/7)}

What is the first derivative of \sqrt[7]{x^2}+2sqrt(x^5) ?

The first derivative of \sqrt[7]{x^2}+2sqrt(x^5) is (2+35x^{31/14})/(7x^{5/7)}

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\frac{2 + 35 x ^{\frac{31}{14}}}{7 x ^{\frac{5}{7}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (2 x^{5}) = 5 x^{\frac{3}{2}}

= \frac{2}{7 x ^{\frac{5}{7}}} + 5 x^{\frac{3}{2}}

Simplify

\frac{2}{7 x ^{\frac{5}{7}}} + 5 x^{\frac{3}{2}} : \frac{2 + 35 x ^{\frac{31}{14}}}{7 x ^{\frac{5}{7}}}

= \frac{2 + 35 x ^{\frac{31}{14}}}{7 x ^{\frac{5}{7}}}

f (x) = x - \frac{1}{x ^{2}}, at x = 1

\int 27 x d x

\int (2 x + 1)^{17} d x

\frac{d}{d x} (tan (x) + y)

6 = \frac{d x}{d t} + \frac{3 x}{20}

What is the derivative of \sqrt[7]{x^2}+2sqrt(x^5) ?
The derivative of \sqrt[7]{x^2}+2sqrt(x^5) is (2+35x^{31/14})/(7x^{5/7)}
What is the first derivative of \sqrt[7]{x^2}+2sqrt(x^5) ?
The first derivative of \sqrt[7]{x^2}+2sqrt(x^5) is (2+35x^{31/14})/(7x^{5/7)}