What is the derivative of f(x)=5\sqrt[5]{x} ?

The derivative of f(x)=5\sqrt[5]{x} is 1/(x^{4/5)}

What is the first derivative of f(x)=5\sqrt[5]{x} ?

The first derivative of f(x)=5\sqrt[5]{x} is 1/(x^{4/5)}

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derivative of

\frac{1}{x ^{\frac{4}{5}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

= 5 \frac{d}{d x} (x^{\frac{1}{5}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 5 \cdot \frac{1}{5} x^{\frac{1}{5} - 1}

Simplify

5 \cdot \frac{1}{5} x^{\frac{1}{5} - 1} : \frac{1}{x ^{\frac{4}{5}}}

= \frac{1}{x ^{\frac{4}{5}}}

\frac{d}{d y} (x) - 0.06 x = 200, y (0) = 0

\frac{d ^{4}}{d x ^{4}} (cos (2 x))

\int \frac{x ^{2} + 5 x + 2}{( x + 1 ) ( x ^{2} + 1 )} d x

x \to - 9 lim (\frac{x ^{2} - 6}{9 - x})

ln (1 - 7 x)

What is the derivative of f(x)=5\sqrt[5]{x} ?
The derivative of f(x)=5\sqrt[5]{x} is 1/(x^{4/5)}
What is the first derivative of f(x)=5\sqrt[5]{x} ?
The first derivative of f(x)=5\sqrt[5]{x} is 1/(x^{4/5)}