What is the derivative of ln(x^2-3) ?

The derivative of ln(x^2-3) is (2x)/(x^2-3)

What is the first derivative of ln(x^2-3) ?

The first derivative of ln(x^2-3) is (2x)/(x^2-3)

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\frac{d}{d x} (ln (x^{2} - 3))

\frac{2 x}{x ^{2} - 3}

Solution steps

\frac{d}{d x} (ln (x^{2} - 3))

Apply the chain rule:

\frac{1}{x ^{2} - 3} \frac{d}{d x} (x^{2} - 3)

= \frac{1}{x ^{2} - 3} \frac{d}{d x} (x^{2} - 3)

\frac{d}{d x} (x^{2} - 3) = 2 x

= \frac{1}{x ^{2} - 3} \cdot 2 x

Simplify

\frac{1}{x ^{2} - 3} \cdot 2 x : \frac{2 x}{x ^{2} - 3}

= \frac{2 x}{x ^{2} - 3}

y = 2 x^{4} - 16 x^{2} + 9, at x = - 4

y = \frac{2}{x}, (5, \frac{2}{5})

\int - 2 x^{- 3} d x

y^{2} = 2 x, x = 2 y

x^{2} y^{^{''}} + x y^{^{'}} - 4 y = 0

What is the derivative of ln(x^2-3) ?
The derivative of ln(x^2-3) is (2x)/(x^2-3)
What is the first derivative of ln(x^2-3) ?
The first derivative of ln(x^2-3) is (2x)/(x^2-3)