What is the integral from 1 to 3 of 3x^2+1/(12x^2) ?

The integral from 1 to 3 of 3x^2+1/(12x^2) is 469/18

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integral from 1 to 3 of 3x^2+1/(12x^2)

\int_{1}^{3} 3 x^{2} + \frac{1}{12 x ^{2}} d x

\frac{469}{18}

Decimal Notation

26.05555 \dots

Solution steps

\int_{1}^{3} 3 x^{2} + \frac{1}{12 x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 3 x^{2} d x + \int_{1}^{3} \frac{1}{12 x ^{2}} d x

\int_{1}^{3} 3 x^{2} d x = 26

\int_{1}^{3} \frac{1}{12 x ^{2}} d x = \frac{1}{18}

= 26 + \frac{1}{18}

Simplify

26 + \frac{1}{18} : \frac{469}{18}

= \frac{469}{18}

x \to 3 lim (- 4)

13 e^{4 t} \cdot e^{2}

\int_{\frac{1}{2}}^{5} 10 x ln (2 x) d x

f (x) = 5 x^{- 15}

f (t) = 1 - cos (t)

What is the integral from 1 to 3 of 3x^2+1/(12x^2) ?
The integral from 1 to 3 of 3x^2+1/(12x^2) is 469/18