What is laplacetransform 13e^{4t}*e^2 ?

The answer to laplacetransform 13e^{4t}*e^2 is (13e^2)/(s-4)

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laplacetransform 13e^{4t}*e^2

laplace transform

13 e^{4 t} \cdot e^{2}

\frac{13 e ^{2}}{s - 4}

Solution steps

L {13 e^{2} e^{4 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 13 e^{2} L {e^{4 t}}

L {e^{4 t}} : \frac{1}{s - 4}

= 13 e^{2} \frac{1}{s - 4}

Refine

13 e^{2} \frac{1}{s - 4} : \frac{13 e ^{2}}{s - 4}

= \frac{13 e ^{2}}{s - 4}

\int_{\frac{1}{2}}^{5} 10 x ln (2 x) d x

f (x) = 5 x^{- 15}

f (t) = 1 - cos (t)

\frac{x d y}{d x} + y = e^{x}

\frac{d}{d x} (tan (x) + x^{4})

What is laplacetransform 13e^{4t}*e^2 ?
The answer to laplacetransform 13e^{4t}*e^2 is (13e^2)/(s-4)