What is derivative of f(x)=2θ-2sin(θ) ?

The answer to derivative of f(x)=2θ-2sin(θ) is derivative of θ=0

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derivative of f(x)=2θ-2sin(θ)

derivative of

f (x) = 2 θ - 2 sin (θ)

\frac{d}{d x} (θ) = 0

Solution steps

f (x) = 2 θ - 2 sin (θ)

Treat

θ

θ (x)

Differentiate both sides:

0 = 2 \frac{d}{d x} (θ) - cos (θ) \frac{d}{d x} (θ)

Isolate

\frac{d}{d x} (θ) : \frac{d}{d x} (θ) = 0

\frac{d}{d x} (θ) = 0

f (x) = \frac{6}{x}, at x = - 2

(7 x + 1)^{2}

x^{2} + 2 x, 2 x + 1

\frac{d}{d x} (25)

\frac{d}{d x} (\frac{tan ( 2 x )}{1 - cot ( 2 x )})

What is derivative of f(x)=2θ-2sin(θ) ?
The answer to derivative of f(x)=2θ-2sin(θ) is derivative of θ=0