What is the derivative of sin(3x+cos(4x)) ?

The derivative of sin(3x+cos(4x)) is cos(3x)*3-sin(4x)*4

What is the first derivative of sin(3x+cos(4x)) ?

The first derivative of sin(3x+cos(4x)) is cos(3x)*3-sin(4x)*4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (sin (3 x) + cos (4 x))

cos (3 x) \cdot 3 - sin (4 x) \cdot 4

Solution steps

\frac{d}{d x} (sin (3 x) + cos (4 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (3 x)) + \frac{d}{d x} (cos (4 x))

\frac{d}{d x} (sin (3 x)) = cos (3 x) \cdot 3

\frac{d}{d x} (cos (4 x)) = - sin (4 x) \cdot 4

= cos (3 x) \cdot 3 - sin (4 x) \cdot 4

\frac{d}{d t} (r (t) cos (t))

3 x y d y = (y^{2} - x^{2}) d x

\int \frac{4}{x} - \frac{16}{x ^{2}} d x

f (x) = (4 x - 1) cos (x)

f (x) = 2^{3} e^{2}

What is the derivative of sin(3x+cos(4x)) ?
The derivative of sin(3x+cos(4x)) is cos(3x)*3-sin(4x)*4
What is the first derivative of sin(3x+cos(4x)) ?
The first derivative of sin(3x+cos(4x)) is cos(3x)*3-sin(4x)*4