What is the integral of xcos(2x^2) ?

The integral of xcos(2x^2) is 1/4 sin(2x^2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of xcos(2x^2)

\int x cos (2 x^{2}) d x

\frac{1}{4} sin (2 x^{2}) + C

Solution steps

\int x cos (2 x^{2}) d x

Apply u-substitution

: \int \frac{cos ( u )}{4} d u

= \int \frac{cos ( u )}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{4} sin (u)

Substitute back

u = 2 x^{2}

= \frac{1}{4} sin (2 x^{2})

Add a constant to the solution

= \frac{1}{4} sin (2 x^{2}) + C

\int \frac{1 + e ^{x}}{e ^{x}} d x

y = \frac{1}{x - 5}, at x = 8

\frac{d}{d x} (cot (1 - 2 x^{2}))

\int \frac{sin ( t )}{cos ( t )} d t

What is the integral of xcos(2x^2) ?
The integral of xcos(2x^2) is 1/4 sin(2x^2)+C