What is the derivative of f(x)=(4x+3)^2 ?

The derivative of f(x)=(4x+3)^2 is 8(4x+3)

What is the first derivative of f(x)=(4x+3)^2 ?

The first derivative of f(x)=(4x+3)^2 is 8(4x+3)

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derivative of

f (x) = (4 x + 3)^{2}

8 (4 x + 3)

Solution steps

\frac{d}{d x} ((4 x + 3)^{2})

Apply the chain rule:

2 (4 x + 3) \frac{d}{d x} (4 x + 3)

= 2 (4 x + 3) \frac{d}{d x} (4 x + 3)

\frac{d}{d x} (4 x + 3) = 4

= 2 (4 x + 3) \cdot 4

Simplify

= 8 (4 x + 3)

x \to 0 lim (tan^{x} (x))

2 x - 4

\int_{- 8}^{0} \frac{y}{8} + y + 9 d y

\int (n + 3)^{3} d n

(- 3, 1), (1, - 2)

What is the derivative of f(x)=(4x+3)^2 ?
The derivative of f(x)=(4x+3)^2 is 8(4x+3)
What is the first derivative of f(x)=(4x+3)^2 ?
The first derivative of f(x)=(4x+3)^2 is 8(4x+3)