What is the integral from-8 to 0 of y/8+sqrt(y+9) ?

The integral from-8 to 0 of y/8+sqrt(y+9) is 40/3

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integral from-8 to 0 of y/8+sqrt(y+9)

\int_{- 8}^{0} \frac{y}{8} + y + 9 d y

\frac{40}{3}

Decimal Notation

13.33333 \dots

Solution steps

\int_{- 8}^{0} \frac{y}{8} + y + 9 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 8}^{0} \frac{y}{8} d y + \int_{- 8}^{0} y + 9 d y

\int_{- 8}^{0} \frac{y}{8} d y = - 4

\int_{- 8}^{0} y + 9 d y = \frac{52}{3}

= - 4 + \frac{52}{3}

Simplify

- 4 + \frac{52}{3} : \frac{40}{3}

= \frac{40}{3}

\int (n + 3)^{3} d n

(- 3, 1), (1, - 2)

sin (4 t) cos (4 t)

\frac{d}{d x} ((3 x^{2} + 5 x) e^{x})

f (x) = 2 x - 2 x

What is the integral from-8 to 0 of y/8+sqrt(y+9) ?
The integral from-8 to 0 of y/8+sqrt(y+9) is 40/3