What is the derivative of q^x+x^q ?

The derivative of q^x+x^q is xq^{x-1}+x^qln(x)

What is the first derivative of q^x+x^q ?

The first derivative of q^x+x^q is xq^{x-1}+x^qln(x)

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derivative of

q^{x} + x^{q}

x q^{x - 1} + x^{q} ln (x)

Solution steps

\frac{d}{d q} (q^{x} + x^{q})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d q} (q^{x}) + \frac{d}{d q} (x^{q})

\frac{d}{d q} (q^{x}) = x q^{x - 1}

\frac{d}{d q} (x^{q}) = x^{q} ln (x)

= x q^{x - 1} + x^{q} ln (x)

\int_{5}^{- 3} 10 x^{2} d x

n = 0 \sum \infty z^{n}

6 sin (θ)

32 y^{^{''}} - 4 y^{^{'}} - 21 y = 0

\frac{d}{d x} (cos (x^{2}) 2 x)

What is the derivative of q^x+x^q ?
The derivative of q^x+x^q is xq^{x-1}+x^qln(x)
What is the first derivative of q^x+x^q ?
The first derivative of q^x+x^q is xq^{x-1}+x^qln(x)