What is the derivative of 14(2e^{x^2}x^2+e^{x^2}) ?

The derivative of 14(2e^{x^2}x^2+e^{x^2}) is 14(4e^{x^2}x^3+6e^{x^2}x)

What is the first derivative of 14(2e^{x^2}x^2+e^{x^2}) ?

The first derivative of 14(2e^{x^2}x^2+e^{x^2}) is 14(4e^{x^2}x^3+6e^{x^2}x)

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derivative of

14 (2 e^{x^{2}} x^{2} + e^{x^{2}})

14 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)

Solution steps

\frac{d}{d x} (14 (2 e^{x^{2}} x^{2} + e^{x^{2}}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 14 \frac{d}{d x} (2 e^{x^{2}} x^{2} + e^{x^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 14 (\frac{d}{d x} (2 e^{x^{2}} x^{2}) + \frac{d}{d x} (e^{x^{2}}))

\frac{d}{d x} (2 e^{x^{2}} x^{2}) = 2 (2 e^{x^{2}} x^{3} + 2 e^{x^{2}} x)

\frac{d}{d x} (e^{x^{2}}) = e^{x^{2}} \cdot 2 x

= 14 (2 (2 e^{x^{2}} x^{3} + 2 e^{x^{2}} x) + e^{x^{2}} \cdot 2 x)

Expand

2 (2 e^{x^{2}} x^{3} + 2 e^{x^{2}} x) + e^{x^{2}} \cdot 2 x : 4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x

= 14 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)

\frac{d}{d z} (x y e^{(x^{2} + z^{2} - 5)})

\int_{0}^{2} 3 4 x + 1 d x

(2 x + 3) d x + (2 y - 2) d y = 0

\frac{d}{d x} (e^{- \frac{4}{x}})

y^{^{'}} = \frac{6 x ^{4} + y ^{4}}{x y ^{3}}

What is the derivative of 14(2e^{x^2}x^2+e^{x^2}) ?
The derivative of 14(2e^{x^2}x^2+e^{x^2}) is 14(4e^{x^2}x^3+6e^{x^2}x)
What is the first derivative of 14(2e^{x^2}x^2+e^{x^2}) ?
The first derivative of 14(2e^{x^2}x^2+e^{x^2}) is 14(4e^{x^2}x^3+6e^{x^2}x)