What is the tangent of f(x)=sqrt(6x),\at x=6 ?

The tangent of f(x)=sqrt(6x),\at x=6 is y= 1/2 x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=sqrt(6x),\at x=6

tangent of

f (x) = 6 x, at x = 6

y = \frac{1}{2} x + 3

Solution steps

Find the tangent point:

(6, 6)

Find the slope of

f (x) = 6 x : \frac{df ( x )}{d x} = \frac{3}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(6, 6) : y = \frac{1}{2} x + 3

y = \frac{1}{2} x + 3

\int \frac{t}{t ^{2} - 1} d t

f (x) = \frac{4}{x}, at 9 \frac{4}{9}

\int \frac{1}{2 x ^{2} + 2 x + 5} d x

\frac{\partial}{\partial x} (x^{\frac{3}{4}} \cdot y^{- 4})

\frac{d}{d x} (4 arcsin (x^{4}))

What is the tangent of f(x)=sqrt(6x),\at x=6 ?
The tangent of f(x)=sqrt(6x),\at x=6 is y= 1/2 x+3