What is the solution for y^{''}+7y^'=0,y(0)=-4,y^'(0)=7 ?

The solution for y^{''}+7y^'=0,y(0)=-4,y^'(0)=7 is y=-e^{-7t}-3

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y^{''}+7y^'=0,y(0)=-4,y^'(0)=7

y^{^{''}} + 7 y^{^{'}} = 0, y (0) = - 4, y^{^{'}} (0) = 7

y = - e^{- 7 t} - 3

Solution steps

y^{''} (t) + 7 y^{'} (t) = 0

Solve linear ODE:

y = - e^{- 7 t} - 3

y = - e^{- 7 t} - 3

\frac{d ^{2}}{d x ^{2}} (\frac{4 x}{x ^{2} + 1})

\int x^{2020} d x

\frac{d}{d x} (ln (1 - \frac{2}{x}))

\int (25 - 0.2 x) d x

f (x) = \frac{1}{9 x}

What is the solution for y^{''}+7y^'=0,y(0)=-4,y^'(0)=7 ?
The solution for y^{''}+7y^'=0,y(0)=-4,y^'(0)=7 is y=-e^{-7t}-3