What is the first derivative of 2+7t ?

The first derivative of 2+7t is 7

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derivative of 2+7t

derivative of

2 + 7 t

7

Solution steps

\frac{d}{d t} (2 + 7 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2) + \frac{d}{d t} (7 t)

\frac{d}{d t} (2) = 0

\frac{d}{d t} (7 t) = 7

= 0 + 7

Simplify

= 7

y^{^{'}} + 2 x^{5} y = \frac{x ^{5}}{y ^{2}}

\frac{10 x}{- 3 y ^{2}}

x \to 0 + lim (\frac{ln ( x )}{x ^{3}})

\frac{x}{x + 2}

\int x^{\frac{5}{3}} ln (x) d x