What is the derivative of sqrt(7x^3-7x^2-(9/x)) ?

The derivative of sqrt(7x^3-7x^2-(9/x)) is (21x^4-14x^3+9)/(2x^{3/2)sqrt(7x^4-7x^3-9)}

What is the first derivative of sqrt(7x^3-7x^2-(9/x)) ?

The first derivative of sqrt(7x^3-7x^2-(9/x)) is (21x^4-14x^3+9)/(2x^{3/2)sqrt(7x^4-7x^3-9)}

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derivative of

7 x^{3} - 7 x^{2} - (\frac{9}{x})

\frac{21 x ^{4} - 14 x ^{3} + 9}{2 x ^{\frac{3}{2}} 7 x ^{4} - 7 x ^{3} - 9}

Solution steps

\frac{d}{d x} (7 x^{3} - 7 x^{2} - \frac{9}{x})

Apply the chain rule:

\frac{1}{2 7 x ^{3} - 7 x ^{2} - \frac{9}{x}} \frac{d}{d x} (7 x^{3} - 7 x^{2} - \frac{9}{x})

= \frac{1}{2 7 x ^{3} - 7 x ^{2} - \frac{9}{x}} \frac{d}{d x} (7 x^{3} - 7 x^{2} - \frac{9}{x})

\frac{d}{d x} (7 x^{3} - 7 x^{2} - \frac{9}{x}) = 21 x^{2} - 14 x + \frac{9}{x ^{2}}

= \frac{1}{2 7 x ^{3} - 7 x ^{2} - \frac{9}{x}} (21 x^{2} - 14 x + \frac{9}{x ^{2}})

Simplify

\frac{1}{2 7 x ^{3} - 7 x ^{2} - \frac{9}{x}} (21 x^{2} - 14 x + \frac{9}{x ^{2}}) : \frac{21 x ^{4} - 14 x ^{3} + 9}{2 x ^{\frac{3}{2}} 7 x ^{4} - 7 x ^{3} - 9}

= \frac{21 x ^{4} - 14 x ^{3} + 9}{2 x ^{\frac{3}{2}} 7 x ^{4} - 7 x ^{3} - 9}

\frac{\partial}{\partial x} (- x y (3 - x - y))

n = 1 \sum \infty \frac{3 n}{2 n + 9}

\int 4 sec^{2} (x) d x

\frac{d}{d x} (x e)

\int \frac{8}{sec ( 2 x ) - 1} d x

What is the derivative of sqrt(7x^3-7x^2-(9/x)) ?
The derivative of sqrt(7x^3-7x^2-(9/x)) is (21x^4-14x^3+9)/(2x^{3/2)sqrt(7x^4-7x^3-9)}
What is the first derivative of sqrt(7x^3-7x^2-(9/x)) ?
The first derivative of sqrt(7x^3-7x^2-(9/x)) is (21x^4-14x^3+9)/(2x^{3/2)sqrt(7x^4-7x^3-9)}