What is the derivative of f(x)=x^{-1/4} ?

The derivative of f(x)=x^{-1/4} is -1/(4x^{5/4)}

What is the first derivative of f(x)=x^{-1/4} ?

The first derivative of f(x)=x^{-1/4} is -1/(4x^{5/4)}

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derivative of

f (x) = x^{- \frac{1}{4}}

- \frac{1}{4 x ^{\frac{5}{4}}}

Solution steps

\frac{d}{d x} (x^{- \frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{4} x^{- \frac{1}{4} - 1}

Simplify

- \frac{1}{4} x^{- \frac{1}{4} - 1} : - \frac{1}{4 x ^{\frac{5}{4}}}

= - \frac{1}{4 x ^{\frac{5}{4}}}

f (x) = e^{\frac{x}{x - 1}}

e^{x}, at x = ln (7)

tan (e^{3 t}) + e^{t a n (3 t)}

f (x) = 7 e^{x} cos (x)

x \to 2 lim (7 - x)

What is the derivative of f(x)=x^{-1/4} ?
The derivative of f(x)=x^{-1/4} is -1/(4x^{5/4)}
What is the first derivative of f(x)=x^{-1/4} ?
The first derivative of f(x)=x^{-1/4} is -1/(4x^{5/4)}