What is (\partial)/(\partial x)((sin(x))/(r^2)) ?

The answer to (\partial)/(\partial x)((sin(x))/(r^2)) is (cos(x))/(r^2)

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(\partial)/(\partial x)((sin(x))/(r^2))

\frac{\partial}{\partial x} (\frac{sin ( x )}{r ^{2}})

\frac{cos ( x )}{r ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{sin ( x )}{r ^{2}})

Treat

r

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{r ^{2}} \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= \frac{1}{r ^{2}} cos (x)

Simplify

\frac{1}{r ^{2}} cos (x) : \frac{cos ( x )}{r ^{2}}

= \frac{cos ( x )}{r ^{2}}

\frac{d}{d x} (9 x^{l n (9 x)})

g (x) = - x^{5} + 4 x^{2} - 2 x + 2

\int \frac{sin ( 2 x )}{18 + cos ^{2} ( x )} d x

\frac{d}{d x} (\frac{4 x ^{5} - 5 x ^{4} + 6 x - 2}{x ^{4}})

y^{^{'}} + 3 y + 5 = 0

What is (\partial)/(\partial x)((sin(x))/(r^2)) ?
The answer to (\partial)/(\partial x)((sin(x))/(r^2)) is (cos(x))/(r^2)