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Popular >

y^'+3y+5=0

Solution

y^{^{'}} + 3 y + 5 = 0

Solution

y = \frac{e ^{- 3 t - c_{1}}}{3} - \frac{5}{3}

Solution steps

y^{'} (t) + 3 y + 5 = 0

Solve separable ODE:

y = \frac{e ^{- 3 t - c_{1}}}{3} - \frac{5}{3}

y = \frac{e ^{- 3 t - c_{1}}}{3} - \frac{5}{3}

Graph

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\int e^{x - 3} d x

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e^{x}, e^{- 3 x}, x = ln (4)

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\int \frac{x ^{2} - 2}{x} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+3y+5=0 ?
The solution for y^'+3y+5=0 is y=(e^{-3t-c_{1}})/3-5/3