What is (\partial)/(\partial x)(e^{-2(x+y)}) ?

The answer to (\partial)/(\partial x)(e^{-2(x+y)}) is -2e^{-2(x+y)}

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(\partial)/(\partial x)(e^{-2(x+y)})

\frac{\partial}{\partial x} (e^{- 2 (x + y)})

- 2 e^{- 2 (x + y)}

Solution steps

\frac{\partial}{\partial x} (e^{- 2 (x + y)})

Treat

y

as a constant

Apply the chain rule:

e^{- 2 (x + y)} \frac{\partial}{\partial x} (- 2 (x + y))

= e^{- 2 (x + y)} \frac{\partial}{\partial x} (- 2 (x + y))

\frac{\partial}{\partial x} (- 2 (x + y)) = - 2

= e^{- 2 (x + y)} (- 2)

Simplify

= - 2 e^{- 2 (x + y)}

f (x) = - 64 x (- 16 x^{2} + 36)

(x^{2} - y^{2}) d x - 2 x y d y = 0

\frac{\partial}{\partial x} ((\frac{x}{y}) e^{x y})

\int 5 x cos (2 x) d x

\frac{d y}{d x}, y = 7 x^{- 4}

What is (\partial)/(\partial x)(e^{-2(x+y)}) ?
The answer to (\partial)/(\partial x)(e^{-2(x+y)}) is -2e^{-2(x+y)}