What is the derivative of x^3+2x^2+1 ?

The derivative of x^3+2x^2+1 is 3x^2+4x

What is the first derivative of x^3+2x^2+1 ?

The first derivative of x^3+2x^2+1 is 3x^2+4x

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derivative of

x^{3} + 2 x^{2} + 1

3 x^{2} + 4 x

Solution steps

\frac{d}{d x} (x^{3} + 2 x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (1) = 0

= 3 x^{2} + 4 x + 0

Simplify

= 3 x^{2} + 4 x

\int \frac{x ^{3}}{3} - \frac{3}{x ^{3}} d x

\int \frac{x ^{2}}{x ^{2} + 9} d x

x \to - π - lim (csc (x))

x^{^{''}} + 2 x^{^{'}} + 2 = 0

n = 0 \sum \infty \frac{10}{3 ^{n}}

What is the derivative of x^3+2x^2+1 ?
The derivative of x^3+2x^2+1 is 3x^2+4x
What is the first derivative of x^3+2x^2+1 ?
The first derivative of x^3+2x^2+1 is 3x^2+4x