What is (\partial)/(\partial x)(cos(y)-x+2y) ?

The answer to (\partial)/(\partial x)(cos(y)-x+2y) is -1

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(\partial)/(\partial x)(cos(y)-x+2y)

\frac{\partial}{\partial x} (cos (y) - x + 2 y)

- 1

Solution steps

\frac{\partial}{\partial x} (cos (y) - x + 2 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (cos (y)) - \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (2 y)

\frac{\partial}{\partial x} (cos (y)) = 0

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (2 y) = 0

= 0 - 1 + 0

Simplify

= - 1

\int (- \frac{y}{x ^{2} + y ^{2}}) d x

\int ln (2 + x^{2}) d x

\int_{0}^{8} \frac{1}{64 + t ^{2}} d t

\frac{d}{d x} (1 + 4 x)

f (x) = (\frac{x + 1}{x - 1})^{2}

What is (\partial)/(\partial x)(cos(y)-x+2y) ?
The answer to (\partial)/(\partial x)(cos(y)-x+2y) is -1