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Popular >

y^{''}+4y=5

Solution

y^{^{''}} + 4 y = 5

Solution

y = c_{1} cos (2 t) + c_{2} sin (2 t) + \frac{5}{4}

Solution steps

y^{''} (t) + 4 y = 5

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t) + \frac{5}{4}

y = c_{1} cos (2 t) + c_{2} sin (2 t) + \frac{5}{4}

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6x(x+3y)y^'=6y(x-3y)

6 x (x + 3 y) y^{^{'}} = 6 y (x - 3 y)

(dy)/(dx)=x^2e^{-4x}-4y

\frac{d y}{d x} = x^{2} e^{- 4 x} - 4 y

limit as x approaches-1 of 2x^3-5x+6x-1

x \to - 1 lim (2 x^{3} - 5 x + 6 x - 1)

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+4y=5 ?
The solution for y^{''}+4y=5 is y=c_{1}cos(2t)+c_{2}sin(2t)+5/4