What is the solution for (20+x^2)y^'-2xy=0 ?

The solution for (20+x^2)y^'-2xy=0 is y=20e^{c_{1}}+e^{c_{1}}x^2

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(20+x^2)y^'-2xy=0

(20 + x^{2}) y^{^{'}} - 2 x y = 0

y = 20 e^{c_{1}} + e^{c_{1}} x^{2}

Solution steps

(20 + x^{2}) y^{'} (x) - 2 x y = 0

Solve separable ODE:

y = 20 e^{c_{1}} + e^{c_{1}} x^{2}

y = 20 e^{c_{1}} + e^{c_{1}} x^{2}

\frac{d}{d x} ((x^{2} + 1))

(4 x - 3)^{4}

f (x) = (- 9 x^{2} + 4)^{2}

\int x arctan (7 x) d x

\frac{d y}{d t} = 5 - 2 y

What is the solution for (20+x^2)y^'-2xy=0 ?
The solution for (20+x^2)y^'-2xy=0 is y=20e^{c_{1}}+e^{c_{1}}x^2