What is the solution for y^'=2sec^2(x)e^{2y} ?

The solution for y^'=2sec^2(x)e^{2y} is y=-(ln(-4tan(x)-c_{1}))/2

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y^'=2sec^2(x)e^{2y}

y^{^{'}} = 2 sec^{2} (x) e^{2 y}

y = - \frac{ln ( - 4 tan ( x ) - c _{1} )}{2}

Solution steps

y^{'} (x) = 2 sec^{2} (x) e^{2 y}

Solve separable ODE:

y = - \frac{ln ( - 4 tan ( x ) - c _{1} )}{2}

y = - \frac{ln ( - 4 tan ( x ) - c _{1} )}{2}

\frac{d}{d x} (\frac{x - 5}{x + 5})

y cos (x y) - tan (x) + x cos (x y) y^{^{'}} = 0

(7, 14), (9, 18)

f (x) = 2 x^{3} - 8 x, (2, 0)

x - sin (x)

What is the solution for y^'=2sec^2(x)e^{2y} ?
The solution for y^'=2sec^2(x)e^{2y} is y=-(ln(-4tan(x)-c_{1}))/2